Bucks’ Malcolm Brogdon named NBA’s Rookie of the Year, Giannis “Most Improved Player”

NEW YORK, NY - JANUARY 04: Malcolm Brogdon #13 of the Milwaukee Bucks in action against the New York Knicks during their game at Madison Square Garden on January 4, 2017 in New York City. NOTE TO USER: User expressly acknowledges and agrees that, by downloading and/or using this Photograph, user is consenting to the terms and conditions of the Getty Images License Agreement. (Photo by Al Bello/Getty Images)

MILWAUKEE — Malcolm Brogdon of the Milwaukee Bucks is the NBA’s Rookie of the Year.

The guard won the first award Monday night, June 26th during the first NBA Awards show that was hosted by Drake. Brogdon beat out finalists Joel Embiid and Dario Saric, both of the Philadelphia 76ers.

Brogdon was a second-round pick out of Virginia who led all rookies with 4.2 assists and 1.12 steals per game in helping the Bucks reach the playoffs.

Embiid had the strongest stats, averaging 20.2 points, 7.8 rebounds and 2.45 blocks, but was limited to just 31 games because of injuries.

Giannis Antetokounmpo won the Most Improved Player award, following Brogdon’s victory for Rookie of the Year to open the show on Monday night.