Aaron Rodgers named Offensive Player of the Week in Week Six

This is an archived article and the information in the article may be outdated. Please look at the time stamp on the story to see when it was last updated.

GREEN BAY — Green Bay Packers’ quarterback Aaron Rodgers has been named Offensive Player of the Week in Week Six of the NFL‘s regular season.

Rodgers and the Green Bay Packers were able to hush their critics – for one day, at least – with a convincing road win against previously unbeaten Houston on Sunday, October 14th. Next they’ll try to win consecutive games for the first time this season.

“Our team has a lot of pride. They have never lost any confidence. I haven’t seen that. I think after (Sunday) night’s win, it’s even stronger,” coach Mike McCarthy said a day after beating the Texans 42-24.

Rodgers completed 24 of 37 passes (64.9 percent) for 338 yards with six touchdowns and no interceptions for a 133.8 passer rating in the Packers’ 42-24 win at Houston.

Rodgers is the first player in NFL history with six TD passes against an undefeated team with at least five wins. He is the first player in franchise history with six touchdowns and no interceptions in a game.

This is Rodgers’ seventh career Player of the Week Award and second in three weeks.

Now, the Packers (3-3) turn their attention to the Rams (3-3), whom they’ll face Sunday, October 21st in St. Louis in the last of three consecutive road games.

Notice: you are using an outdated browser. Microsoft does not recommend using IE as your default browser. Some features on this website, like video and images, might not work properly. For the best experience, please upgrade your browser.